Author Archives: ANG KHENG
Second last TBL session – Energetics Assignment
Homework! Reaction Kinetics Group Hall-work
Week 10 Carbonyl Compounds Reactions (in-class questions)
Minutes – Meeting on applications
Time: 2pm
Date: 28/09/15
Meeting agenda: Applications on MO Theory
Location: 18A/B TV lounge
It was the recess week. Yet, it wasn’t quite like the recess week as we were still very much drowning in schoolwork. We met up this fateful day to work on the applications of what we had learnt before the recess week, MO Theory. Prior to this, we had some interesting inspirations and coupled with the bad haze, we decided to work on explaining an Oxygen detector. Perhaps, there could come a time when we would be struggling to keep ourselves from suffocating at the rate the haze was worsening.
Fortunately, when we went online, we found relevant real life machinery based on our extensive searching. We tried hard to figure the mechanism upon which the machinery worked on. We had disagreements and was nearly thrown in heated arguments. Fortunately, MO Theory bonded us together and we worked as a team whereby we successfully figured out how. Thumbs up to the team!
Bond Order 1, 2, 3? Let’s go!
Now that we have seen the usefulness of MO theory over valence bond theory, let’s take a look at how we can use the theory by finding the bond order of a molecule.
Previously, we have learnt how to fill the molecular orbitals following the Aufbau’s principle, Hund’s Rule and the Pauli’s Exclusion Principle. Now, we are going to use that molecular orbitals diagram to find the bond order. Read on to find out how!
Bond order
The concept of bond order in layman terms can be described as the average number of electrons involved per bond in a molecule.
It is based on the formula, B.O. = ½ [ no. of bonding electrons – no. of anti-bonding electrons].
As an example, let’s look at oxygen below.
Bond order in O2 = ½ [ no. of bonding electrons – no. of anti-bonding electrons] = ½ [ 10 – 4 ] = 2
Hence an average of 2 electrons are involved in a bond in O2.
In reality, the dot and cross diagram does prove that to be true, as shown below.
You may want to try calculating the bond order for other molecules.
Try the example below:
Remember, bond order in O2 = ½ [ no. of bonding electrons – no. of anti-bonding electrons]
Answer: B.O.= 1
The bond order generally tells us the strength of the bond. The higher the bond order, the stronger the bond. We may make use of bond strength to further discuss about the stability of a molecule or the melting/boiling point. Yep, it’s that useful! Let me know if you find another use for it, it might be unheard of!
Magnetic Properties Prediction from MO Diagram
Alright, now that we have grasped the concept of bond order, we shall move on to another important concept which will help us predict an important property of a molecule – its magnetic properties! Here are 2 terms describing the magnetic property of a molecule:
1. Diamagnetic – This occurs when a molecule possess no singly paired electrons, and thus is not attracted to magnetic fields.
2. Paramagnetic – This occurs when a molecule possess singly paired electrons and is will be attracted to magnetic fields.
Example:
As observed in the MO Diagrams of Oxygen and Fluorine, we note that Oxygen has 2 unpaired electrons whereas Fluorine has none. Hence we can conclude that Oxygen is Paramagnetic whereas Fluorine is Diamagnetic.
What is Heteronuclear Diatomic? o.o
Heteronuclear diatomic molecules are composed of two atoms of two different elements. The same electronic shell of the two atoms may not be of the same energy. That being said, it is not necessary for the electronic orbitals of the same shell to interact to give molecular orbitals. In fact, it is not necessary for the two 1s orbitals to interact. the 1s orbital may interact with other electronic orbitals, for example, this can be seen in the MO diagram of HF, below.
Figure 1: Molecular orbital of HF (Courtesy of chemwiki.ucdavis.edu)
The 1s orbital of H is of much similar energy to that of 2p in F. Therefore, interaction between the 1s and 2p orbitals takes place to form the molecular orbital of HF. Such electronic orbital interactions is common in heteronuclear diatomic as the electronic orbitals usually differ in energy levels.
In the molecular orbitals formed, a bonding and an anti-bonding molecular is formed. The molecules, H and F, contribute differently to each of these molecular orbitals. H contributes more to the anti-bonding orbitals as it is closer in energy to it. Likewise, F contributes moreto the bonding molecular orbital. The unequal contribution means that the covalent bond has a certain degree of ionic character.
Yes, so.. Do not be surprised the next time you see a 1s interacting with another 2p, 3s, 3p, who knows what orbital!
Meeting minutes 17/09/2015
Time: 9pm
Date: 17/09/15
Meeting agenda: TBL group question 5
We were very enlightened about the structures of the organic compounds using our newly bought USD52 modeling toys! They seemed so delicate but yet so strong that it actually pulled through our twisting and pulling.. We were extremely confused with the definitions of the terms in the process of determining if a compound was a diastereomer. However, we got past the technicalities by putting our heads together. 🙂
After we were enlightened by the models, the next step was to present the answers. We initially thought that we should put chemdraw into action but decided that the previous mind-blowing information had drawn all of us of our energy. So we decided not to deal with the technical difficulties of chemdraw but instead put them on traditional paper and pen.
Presenting to you, our answers!
Group Assignment 3 Q6
According to the MO diagram in the picture above, we have determined that there are two sigma bonds, two pi bonds, and four lone pairs in the azide anion. We can also see from the MO diagram that there are no unpaired electrons in the anion, so it must be diamagnetic. The atoms that have the greatest electron density are the atoms bonded to the central N atom.