Computer Interface & Magnetic Hard-disk

Dear Prof Teo

Do you mind explaining tutorial 5.2 question 3f

(the answer is attached in this email) on how do you actually get the oversampled frames (2x)? How do you get from original 1011001 to 0110011 and 0001100? I don’t quite catch the part how to convert it.

[Jason] Every bit is sampled twice. The original data packet is 10 bits. The oversampled data is 20 bits, so it is two frames, since the receiver expects a data frame of 10 bits.

And .. I have attached an image in this email,

IMG-20140327-WA0046-1

I did a question, but do not quite understand do I need to multiply the amount of cylinders and recording surfaces to find average data transfer rate. As from what I understand, total time is no of bytes/(RPS*Track density*Sector density), but if there is a stated amount of cylinders and recordings stated, do I require to multiply with the (RPS*Track density*Sector density)?

[Jason] 16 recording surfaces and 12000 cylinders imply there are 12000 tracks on each platter.

And, if we are ask to draw waveform of data frame, is it required to draw the idle part?

[Jason] It is easier to read the waveform if the idle portion is drawn as well. But, you will not be penalized, if otherwise.

Thank you in advance.

Yours Sincerely

Apple Tan Xuan Ning